# Physics Lesson 3.7.4 - Average and Instantaneous Acceleration

Welcome to our Physics lesson on Average and Instantaneous Acceleration, this is the fourth lesson of our suite of physics lessons covering the topic of The Meaning of Acceleration. Constant and Non-Constant Acceleration. Gravitational Acceleration, you can find links to the other lessons within this tutorial and access additional physics learning resources below this lesson.

## Average and Instantaneous Acceleration

As we have stated in the tutorial Speed and Velocity in One Direction, rarely occurs that an object keeps moving at the same velocity during the entire motion. The same thing can be said for the constant acceleration as well. It is quite impossible an object keeps accelerating at the same rate during its motion, as many other factors such as the resistive forces caused by the air etc., are not constant. We will see in the Physics tutorial Types of Forces II. Resistive Forces (Frictional Force. Drag). Terminal Velocity that air resistance increases when an object is moving faster than before. This brings a decrease in the acceleration until it becomes zero. As a result, the object successively will move at constant velocity.

Another similar example consists in a scenario in which a driver presses the brakes near the traffic lights and after a while (when the green light turns on), he presses the gas pedal. It is obvious this is an irregular motion although it may be rectilinear. This irregularity results in the impossibility to consider the motion as a whole. In this case, we can use one of the two following approaches:

1. Splitting the motion in small regular sections and finding the required quantities (here the acceleration) one by one before making any generalization, or
2. Considering the motion as a whole and calculating only the average values of the entire motion. In this tutorial, we are interested only in the average acceleration which is obtained by the following equation:
< a > = ∆vtot/ttot

The second method is much shorter and easier because we need to know only three quantities: the two values of velocity (the initial and the final velocity) and the total time taken.

On the other hand, the instantaneous acceleration shows the acceleration at a given instant, similarly to the instantaneous velocity we discussed in the previous tutorials. Thus, if we are required to find the instantaneous acceleration in a certain instant t, we need to consider a very narrow time interval Δt around the given instant and calculating the respective velocities v1 and v2 for the two bordering points of the interval. Then, using the equation

a = ∆v/∆t = v2 - v1/t1 - t1

we find the value of the instantaneous acceleration.

To help understand this point, a velocity vs time graph is shown below.

Let's suppose we are required to find the average acceleration t = 1.0 s. For this, we have to consider two surrounding points close to the given coordinate. For example, we can take t1 = 0.6 s and t2 = 1.4 s. Therefore, Δt = t2 - 1 = 1.4 s - 0.6 s = 0.8 s.

From the graph, it is easy to find that the respective values of velocity for these time values are v1 = 11 m/s and v2 = 13 m/s. Hence, we obtain for the instantaneous velocity in the given interval:

a = ∆v/∆t
= v2-v1/t1 - t1
= 13 m/s - 11 m/s/1.4 s - 0.6 s
= 2 m/s/0.8 s
= 2.5 m/s2

### Example 1

An object starts moving from rest and it reaches a velocity of 16 m/s in 8 seconds. Then, it starts decelerating for the next 10 seconds until it comes to rest again.

Calculate:

1. The average acceleration during the first interval (during the first 8s)
2. The average acceleration during the second interval (during the next 10s)
3. The total average acceleration

### Solution 1

The initial velocity is usually written in problems as u or v0; it is rarely written as v1 or vi. Also, the final velocity is often written as v instead of v2 or vf. Therefore, we can write the following values as clues:

u = 0
v1 = 16m/s
Δt1 = 8s
v = 0
Δt2 = 10s

We have to find < a1 >, < a2 > and < atot > because we are not sure about how the object has moved; we only know the three values of velocity. No information regarding any possible motion with constant acceleration is provides. For this reason, we can only calculate the average values of acceleration, not the instantaneous acceleration in any section of motion.

The average acceleration during the first interval is:

< a1 > = v1-u/∆t1
= 16 m/s - 0 m/s/8s
= 2 m/s2

The average acceleration during the second interval is:

< a2 > = v-v1/∆t2
= 0 m/s - 16 m/s/10s
= -1.6 m/s2

Since the initial and final velocities are both zero, the total average acceleration is:

< atot > = ∆vtot/ttot
= v - v0/ttot
= 0 - 0/8s + 10s
= 0/18s = 0

This is obvious because the positive acceleration in the first interval is cancelled out by the negative acceleration in the second interval.

Be careful to avoid taking the arithmetic mean of the two accelerations as in this case you get a wrong result. The only case in which it is allowed to calculate the average acceleration by finding the arithmetic mean is when the time intervals are equal.

You have reach the end of Physics lesson 3.7.4 Average and Instantaneous Acceleration. There are 5 lessons in this physics tutorial covering The Meaning of Acceleration. Constant and Non-Constant Acceleration. Gravitational Acceleration, you can access all the lessons from this tutorial below.

## More The Meaning of Acceleration. Constant and Non-Constant Acceleration. Gravitational Acceleration Lessons and Learning Resources

Kinematics Learning Material
Tutorial IDPhysics Tutorial TitleTutorialVideo
Tutorial
Revision
Notes
Revision
Questions
3.7The Meaning of Acceleration. Constant and Non-Constant Acceleration. Gravitational Acceleration
Lesson IDPhysics Lesson TitleLessonVideo
Lesson
3.7.1The meaning of Motion Maps
3.7.2The meaning of Acceleration
3.7.3Constant and non-constant acceleration
3.7.4Average and Instantaneous Acceleration
3.7.5Gravitational acceleration

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