Calculator™ © - Free Online Calculators

Online Calculators since 2009

- Torque Calculator
- Conservation Of Momentum In 1 D Calculator
- Gravitational Field Strength Calculator
- Surface Tension Force Calculator
- Physics Tutorial: Position and Reference Point
- Conservation Of Momentum In 2 D Calculator
- Image Position And Magnification In Curved Mirrors And Lenses Calculator
- Lame's First Parameter in Three Dimensional Calculator
- Electric Flux (Gauss Law) Calculator
- Roche Limit Calculator
- Equilibrium Using Moments Calculator

In this Physics tutorial, you will learn:

- The meaning of Reference Point
- What is Position?
- What is Location and where does it differ from Position?
- How to express the Position in a system of coordinates?

In the previous Physics Tutorial, "Types of Motion", we described the motion as "the phenomenon in which an object changes its location over time." But, is it always easy to know whether an object is moving or not?

Consider the following examples:

- You are looking at the downloading bar on a PC screen when a very heavy file is being downloaded and the internet is very slow.
- You are observing the stars during the night in a clear sky.
- You are looking the minutes hand of a wall clock.

Is it easy to detect any motion in the above examples? Why?

Which action would help you find whether the abovementioned objects are moving or not? Why?

Let's try to explain the concept of reference point by providing answers to the questions posed in the "Introduction" section.

**1.** The downloading bar seems unmoveable. At first sight, it seems the downloading process has stopped. You can check this by putting the cursor at the end of the orange bar, which shows the downloading progress. After a while, you can check whether the orange bar has moved on the right of the cursor or not. If yes, the downloading process is active. Therefore, the cursor acts as a reference point for you as it helps understanding whether the downloading progress bar is moving or not.

Look at the figure below:

**2.** The bright star is slightly on the left of pyramid in the first figure. After a while, it "shifts" on the right of the pyramid. In this way, the pyramid acts as a reference point, which helps us to understand whether the stars are in the same place as before or they "have moved".

Look at the figure:

**3.** In the figure below, the star in the wall helps us understand that the clock is working properly as the minute hand has moved in respect to the star. Therefore, it (the star) acts as a reference point.

In all the above examples, it was clearly outlined the necessity and importance of a reference point from which we start making any measurement or estimation in order to detect any change in object's location.

Thus, by definition, **"A fixed point with respect to which a body changes its location is called Reference Point or Origin."**

When dealing with calculations in Kinematics, reference point is usually the origin of the coordinate system, no matter whether the system is 1, 2 or 3 dimensional. Reference point (origin) is usually denoted by the number 0 or the letter O.

We can show the location of an object by a finger, or by drawing a small dot in the place where the object lies. If the object is voluminous, we usually put a small dot at the object's centre to show its location as in the figure below.

It is obvious that location does not imply the use of any reference point or coordinate. Therefore, no numerical values are involved when dealing with the location of an object.

On the other hand, **Position** is a physical quantity that shows how far an object from the origin (reference point) is. Position not only has a magnitude (numerical value) but it also has a direction. It is not the same thing if we say, "the object is 6m on the left of the reference point" and "the object is 6m on the right of the reference point" although the distance from the origin (reference point) is the same in both cases (6 m).

Thus, there are two men in the figure; each of them is at 6m from the tree, which in this case acts as a reference point or origin. Therefore, it is obvious it is not enough knowing only the distance from the reference point but we must know the direction as well. Only then, we can exactly determine the position of a given object.

As we discussed in Physics Tutorial 2.1 "Vectors and Scalars in Physics", a quantity for which direction information is required is known as "vector quantity." This is the case for the position of an object.

By definition, **"Position is a vector quantity that shows how far an object is from the origin in a given direction."**

Position can be positive, negative or zero. It can be positive when the location of the object is at the positive part of the position axis. For example, the position of the green bicycle shown below is positive as its location is at (+4) m. As for the position of the blue bicycle, it is negative because its location is at (-1) m. (Remember, for voluminous and irregularly shaped objects we consider the actual location at the centre of the object). Position can be zero when the object is located at the reference point.

It is known that in a system of coordinates we can assign a letter to each direction available. Thus, if there is only one direction available (1-D) as shown in the above figure, we denote the axis by the letter x and the object's position by the vector x*⃗* or Ox)*⃗*. We can write

x*⃗*_{blue bicycle} = -1 m

and

x*⃗*_{green bicycle} = +4 m

When two directions of motion (2-D) are available, we can express the position of an object using a pair or coordinates (one for each direction). We must use two letters (usually x and y) to label the directions. Therefore, we need to know both coordinates to determine the location of an object in 2-D. Look at the figure below:

From the above graph, we can see that the object A is 4m on the right and 2m above the reference point. Therefore, we say the position of the object A is at (4m, 2m) and by this, we understand that the position of object A is represented through the vector

OA*⃗* = *4m**/**2m*

and the object A is

|OA*⃗*| = √**OA**^{2}_{x} + OA^{2}_{y}

= √**4m**^{2} + 2m^{2}

= √**20m**^{2}

= 4.47m

= √

= √

= 4.47m

away from the origin in the direction of the vector OA*⃗*.

Likewise, we can use the same approaches in 3-D (in space) as well. We have another direction added in this case. Usually, it is denoted by the letter z. Therefore, we must write all three coordinates to determine the position of an object. Look at the graph below.

The object A is in the 3 dimensional space. It is diverted 6m from the origin according the x-direction, 5 m from the origin in the y-direction and 6m from the origin in the z-direction, all in the positive direction. This means the components of the vector OA*⃗* which represents geometrically the linear distance from the origin, are OAx = 6m, OAy = 5m and OAz = 6m respectively.

From the concept of vector's magnitude, we know that

|OA*⃗*| = √**OA**^{2}_{x} + OA^{2}_{y} + OA^{2}_{z}

Therefore, substituting the values, we obtain for the magnitude of the vector OA*⃗*

|OA*⃗*| = √**(6m)**^{2} + (5m)^{2} + (6m)^{2}

= √**36m**^{2} + 25m^{2} + 36m^{2}

= √**97m**^{2}

= 9.85m

≈ 10m

= √

= √

= 9.85m

≈ 10m

Thus, the object A is nearly 10m away from the origin (reference point) in the direction of the vector OA*⃗*.

Write the position of the objects A, B and C shown in the figure. How far are they from the origin?

The object A is in the xOy plane. It has no z-coordinate, so we need to know only two coordinates to show its position.

From the figure, we can see that Ax = 4m, Ay = 3m (and Az = 0m). Therefore, the position OA*⃗* of the object A is

OA*⃗* = __4m____3m____0__

The distance from the origin of the Object A is found by calculating the magnitude of the vector OA*⃗*. Therefore, using the known procedure explained in the article "Vectors and Scalars" for calculating the magnitude of a vector, we can write

|OA*⃗*| = √**OA**^{2}_{x} + OA^{2}_{y} + OA^{2}_{z}

Substituting the values, we obtain for the magnitude of the vector OA*⃗*

|OA*⃗*| = √**(4m)**^{2} + (3m)^{2} + (0m)^{2}

= √**16m**^{2} + 9m^{2}

= √**25m**^{2}

= 5m

= √

= √

= 5m

This means the point A is 5m away from the origin in the direction of the vector OA*⃗*.

The same procedure is used for the other two objects. Thus, for the object B we have only one coordinate Bz = 5m as it lies on the z-axis only. It is not necessary to calculate the magnitude of the vector OB*⃗* as it is clear that |OB*⃗*|= 5m.

As for the object C, we can see from the figure that it contains all three coordinates. Thus, Cx = 3m, Cy = 6m and Cz = 4m. Therefore, the magnitude of the vector OC*⃗* which represents the position of the object C (its linear distance from the origin), is

|OC*⃗*| = √**OC**^{2}_{x} + OC^{2}_{y} + OC^{2}_{z}

Substituting the values, we obtain for the magnitude of the vector (OC)*⃗*

|OC*⃗*| = √**(3m)**^{2} + (6m)^{2} + (4m)^{2}

= √**9m**^{2} + 36m^{2} + 16m^{2}

= √**61m**^{2}

= 7.81m

= √

= √

= 7.81m

Therefore, the object C is 7.81m away from the origin in the direction of the vector OC*⃗*.

The figure below shows the position vectors for the three objects.

**Remark!** The 1 and 2 dimensional motions are special cases of the 3 dimensional motion. We can either write 0 in the place of the missing coordinates or simply represent the position in as many coordinates as given. We can illustrate this aspect using the position of the vector B. This position can be mathematically represented in three ways:

In one dimension (according z only)

OB*⃗* = 5m

In two dimensions (according x and z, or y and z)

OB*⃗* = __0____5m__

In three dimensions (according x, y and z)

OB*⃗* = __0____0____5m__

All these three presentations show the same thing: the vector OB*⃗*. Hence, they are all equivalent.

A fixed point with respect to which a body changes its location is called Reference Point or Origin.

When dealing with calculations in Kinematics, the reference point is usually the origin of the coordinate system, no matter whether the system is 1, 2 or 3 dimensional. The reference point (origin) is usually denoted by the number 0 or the letter O.

The concept of Location is different from that of Position. Thus, Location does not imply the use of any reference point or coordinate. Therefore, no numerical values are involved when dealing with the location of an object.

On the other hand, Position is a physical quantity that shows how far an object from the origin (reference point) is. Position not only has a magnitude (numerical value) but it also has a direction. Given this, position can be positive, negative or zero depending on which part of the reference point it is.

In a system of coordinates, we can assign a letter to each direction available. Thus, if there is only one direction available (1-D), we denote the axis by the letter x and the object's position by the vector x*⃗* or Ox*⃗*.

When two directions of motion (2-D) are available, we can express the position of an object using a pair or coordinates (one for each direction). We must use two letters (usually x and y) to label the directions. Therefore, we need to know both coordinates to determine the location of an object in 2-D.

Likewise, we can use the same approaches in 3-D (in space) as well. We have another direction added in this case. Usually, it is denoted by the letter z. Therefore, we must write all three coordinates to determine the position of an object.

The 1 and 2 dimensional motions are special cases of the 3 dimensional motion. We can either write 0 in the place of the missing coordinates or simply represent the position in as many coordinates as given.

*1. An airplane is 47 miles due North and 72 miles due West of the Command Centre of Air-Traffic Control at 6 miles of altitude. How far is the airplane from the Command Centre building? Express the answer to one decimal place (to one tenths of a mile). *

- 86.0 miles
- 85.9 miles
- 125.0 miles
- 86.2 miles

**Correct Answer: D**

*2. Which of the objects shown in the figure is closer to the origin?*

- Object A
- Object B
- Object C
- Object D

**Correct Answer: C**

*3. Which of the following statements is WRONG? *

- An object with coordinates (3m, 4m, 0m) has the same position as another object with coordinates (5m, 0m, 0m)
- An object with coordinates (3m, 4m, 0m) has the same distance from the origin as another object with coordinates (5m, 0m, 0m)
- An object with coordinates (3m, 4m, 0m) has the same location as another object with coordinates (5m, 0m, 0m)
- An object with coordinates (3m, 4m, 0m) occupies the same space as another object with coordinates (5m, 0m, 0m)

**Correct Answer: B**

We hope you found this Physics tutorial useful, if you did. Please take the time to rate this tutorial and/or share on your favourite social network. In our next tutorial, we explore Displacement and Distance in 1 Dimension..

The following Physics Calculators are provided in support of the Kinematics tutorials.

- Uniform Motion Calculator
- Uniformerly Accelerated Decelerated Motion Calculator
- Projectile Motion Calculator

You may also find the following Physics calculators useful.

- Buoyancy Calculator
- Elastic Force And Elastic Potential Energy Calculator
- Self Inductance Calculator
- Magnetic Field Inside A Long Stretched Current Carrying Wire Calculator
- Joules Law Calculator
- Resistance Due To Temperature Calculator
- Newtons Second Law For A System Of Particles Calculator
- Impedance Calculator
- Orbit Pericenter Distance Calculator
- Bohr Radius Of Hydrogen Like Atoms Calculator
- Torque Calculator
- Electron Debye Length Calculator
- Radiative Heat Transfer Calculator
- 1 D Work Calculator
- The Doppler Effect In Sound Waves Calculator
- Kinetic Energy Calculator
- Self Inductance Of Coil Calculator
- Capacitance Of Parallel Cylinders Calculator
- Entropy Calculator
- Hydraulic Cylinder Pull Force Calculator