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Motion in Two Dimensions. Projectile Motion

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3.12Motion in Two Dimensions. Projectile Motion


In these revision notes for Motion in Two Dimensions. Projectile Motion, we cover the following key points:

  • What is a projectile?
  • How to divide the study of a projectile?
  • What kinds of motion are involved in a projectile?
  • What are the equations used during the study of a projectile?

Motion in Two Dimensions. Projectile Motion Revision Notes

Projectile motion is a kind of motion experienced by an object that is projected near the Earth's surface and moves along a curved path under the action of gravity only (if the effects of air resistance are assumed to be negligible). This curved path is a parabola. The study of such motions is called ballistics, and such a trajectory is known as a ballistic trajectory.

The direction of the initial velocity vector is according the tangent to the line at the given point.

In absence of air resistance, the only acceleration acting on a projectile is the gravitational acceleration g. It is a vertical (downward) acceleration, therefore the horizontal part of the motion does not contain any acceleration (it is a uniform motion). Hence, it is necessary to study the horizontal and the vertical components of projectile separately because the horizontal component represents a uniform motion and the vertical component a uniformly decelerated motion when moving up and a uniformly accelerated motion when falling down.

The equations of projectile are:

Horizontally,

∆x = v0x × ttot
= v0 × cos θ × ttot

and vertically,

Equation 1

vy = v0y + g × t
vy = v0 × sin θ + g × t

Or

Equation 2

∆y = (vy + v0y) × t/2
∆y = (vy + v0 × sin θ) × t/2

Or

Equation 3

v2y - v20y = 2 × g × ∆y
v2y - (v0 × sin θ )2 = 2 × g × ∆y

Or

Equation 4

∆y = v0y × t + g × t2/2
∆y = v0 × sin θ × t + g × t2/2

The last equation is known as the equation of motion for the vertical component of a projectile. Thus, we have

∆y = v0 × sin θ × t + g × t2/2
y - y0 = v0 × sin θ × t + g × t2/2

Or

y = y0 + v0 × sin θ × t + g × t2/2

Therefore, the vertical position y as a function of time t is

y(t) = y0 + v0 × sin θ × t + g × t2/2

It allows us to determine the vertical position of an object at every instant t when the initial parameters (the initial vertical coordinate y0 and the initial velocity v0) are known.

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