Physics Lesson 16.10.2 - Rate of Work (Power)

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Welcome to our Physics lesson on Rate of Work (Power), this is the second lesson of our suite of physics lessons covering the topic of Induction and Energy Transfers, you can find links to the other lessons within this tutorial and access additional physics learning resources below this lesson.

Rate of Work (Power)

From Dynamics, we know that to pull something at constant velocity, we must apply a constant force, which equals in magnitude the resistive forces. This fact is true in this case as well. We have seen earlier that the pulling force F is opposed by a magnetic force F_m that opposes it. Thus, we have equilibrium only when |F| = |F_m|. In such a case, the coil moves at constant speed.

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The rate of work (i.e. the mechanical power) done by the external force F when moving the coil inside a uniform magnetic field is

P = F ∙ v

Now, let's find an expression for the power P in terms of magnetic field B and other related quantities such as the resistance of coil R and its length L.

As stated earlier, when we shift the coil due right, the area punched by the magnetic field lines decreases. As a result, the magnetic flux decreases too. This means a current is induced in the coil; this current produces a magnetic force F_m that opposes the cause of its creation (the pulling force F).

You have reached the end of Physics lesson 16.10.2 Rate of Work (Power). There are 6 lessons in this physics tutorial covering Induction and Energy Transfers, you can access all the lessons from this tutorial below.

More Induction and Energy Transfers Lessons and Learning Resources

Magnetism Learning Material
Tutorial ID	Physics Tutorial Title	Revision Notes	Revision Questions
16.10	Induction and Energy Transfers
Lesson ID	Physics Lesson Title	Lesson	Video Lesson
16.10.1	Induction and Energy Transfer
16.10.2	Rate of Work (Power)
16.10.3	Induced Emf
16.10.4	Induced Current
16.10.5	Power and Energy
16.10.6	Eddy Currents

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