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In this Physics tutorial, you will learn:

- What is the definition of Lentz Law? What do we find using it?
- How the Lentz Law is related to the Faraday's Law of Induction?
- What strategy do we use to solve problems involving the implementation of Lentz Law?
- What is the induced magnetic field? When does it appear?
- What happens to the magnetic flux when a magnet moves towards to or away from a coil?

You are walking near a dangerous dog. What do you do in this case? Is it a good idea to assault the dog first in order to protect yourself? Why? What is the best thing to do in this case?

What is the direction of induced current produced in a coil? How do you know this?

What happens to the magnetic flux when we move a magnet towards or away from a coil?

This tutorial explains the rules how to determine the direction of induced current flow in a magnetic field. We have already touched this topic earlier but now we will explain it more extensively, in order to provide a full explanation of this phenomenon (induced current).

In the previous tutorial, we explained the Faraday's Law, which expresses the induced emf as a rate of flux change. The mathematical expression of Faraday's Law is

ε_{i} = -N ∙ *∆Φ*_{M}*/**Δt*

The minus sign in Faraday's law of induction is very important. The negative sign means that **the induced emf creates a current (induced current) and magnetic field (induced magnetic field) that oppose the change in flux. This statement is known as the Lenz's Law** .

It is not very common in Physics that a minus placed in the formula of a certain law (here Faraday's Law) produces another law (Lentz Law). This means the direction of the induced emf in a coil is very important. Faraday was aware of the direction, but Lenz stated it explicitly, so he is credited for its discovery.

When we move a magnet towards to or away from a coil, we must consider two magnetic fields: one is the magnetic field B possessed by the magnet and the other is a new magnetic field produced in the coil due to the presence of the induced current. This new magnetic field is known as the induced magnetic field B_{i} and it can be in the same or opposite direction of the original magnetic field produced by the moving magnet.

We can think this phenomenon similar to when we walk near a dog as mentioned in the beginning of this tutorial. If we assault the dog, it will rush against us but if we try to avoid the dog, the chance to be unharmed by the end of this situation increases.

The strategy used to solve problems involving the Lentz Law consists on the following steps:

- Making a sketch that helps is a better understanding of situation through visualization.
- Determining the direction of the magnetic field B.
- Determining whether the flux is increasing or decreasing.
- Determining the direction of the induced magnetic field B
_{i}. It is either added to or subtracted from the original field, depending on how the magnet is moving or which pole is near the loop. However, one thing is sure: it always opposes the motion. - Using the Right Hand Rule to determine the direction of the induced current that is responsible for the induced magnetic field B
_{i}. - The direction (or polarity) of the induced emf will now drive a current in this direction and can be thought as current emerging from the positive terminal of the emf and returning to its negative terminal.

Let's consider an example to make this point clear. If a magnet is moving towards a coil as shown in the figure,

a new magnetic field is generated because of the current induced in the coil as a result of magnet's motion. This induced magnetic field B_{i} opposes the magnet's motion and if considered the above figure, the direction if the induced magnetic field is as shown below:

Since an induced current is produced due to the magnet's motion relative to the coil, an emf is induced in the coil as well. Therefore, the magnetic flux in the coil changes based on the Faraday's Law:

ε_{i} = -N ∙ *∆Φ*_{M}*/**Δt*

If the magnet moves in the direction shown in the figure (towards the coil), the magnetic flux increases because more magnetic field lines enter the coil. This is obvious from geometry as when we move the magnet closer to the coil, the angle formed by the magnetic pole and the coil increases and as a result, more field lines enter the coil. As a result, the total magnetic field produced is

B_{tot} = B + B_{i}

where B is the original magnetic field produced by the magnet and B_{i} is the induced magnetic field produced when the magnet moves towards the coil.

When the magnet moves in the opposite direction, the magnetic field of magnet is still in the original direction as the magnet only displaces horizontally; its poles does not change direction. However, an induced magnetic field in the opposite direction will be produced due to the induced current and **emf** of the coil. They also change direction to the previous case and thus, we obtain the setup shown in the figures below:

The magnetic flux in this case decreases with time as less magnetic field produced by the mar magnet enter the coil. As a result, an **induced emf** (and therefore an **induced current**) will appear in the coil based on the Faraday's Law. This induced current is in the opposite direction to before.

A copper coil is placed inside a uniform magnetic field where the plane of coil is normal to the field lines. A copper ring slides downwards from position 1 to position 6 as shown in the figure. Determine the direction of the induced current (if any) for each position.

- There is no induced current in the coil in the position 1 despite it is moving downwards. This is because the coil in outside the magnetic field. Remember, an induced current is produced only when a coil is moving in respect to an external magnetic field.
- The coil is increasing its velocity at the position 2. This means the number of magnetic field lines entering the coil is increasing with time, so the magnetic flux in the coil is increasing too (this is similar to when we move a bar magnet towards a coil as discussed earlier). Hence, the induced flux must be directed outwards since the external magnetic field is directed onto the page (inwards). In order to produce an outward induced magnetic field, the induced current in the coil must be in the anticlockwise direction (you can prove it using the right hand rule).
- The coil is moving slower than before in the position 3. This means the number of magnetic field lines entering the coil is decreasing with time, so the magnetic flux in the coil is decreasing too. Hence, the induced flux is directed inwards. The resulting induced current in the coil is therefore clockwise (use again the right hand rule to convince yourself).
- The coil is moving at constant velocity when it is in the position 4 (v
_{3}= v_{4}as the arrows showing the velocity are identical in these two positions). Therefore, no flux change is occurring. This means no induced emf (and induced current) is being produced in the coil and ΔΦ = 0. - In the position 5, the coil is not moving, so actually there is no induced current in the coil. (When moving from position 4 to position 5 there is a decrease in velocity, so the situation is similar to 3 (there is a decreasing flux which brings an inwards induced flux and a clockwise induced current in the coil).
- In the position 6, the coil is outside the magnetic field, so there is no induced current produced in the coil despite it is moving. This situation is similar to that described in the position 1.

Now, we can discuss a numerical example to make clear this point (how to apply the Lentz Law).

A rectangular coil of area 0.4 m_{2} is placed inside a uniform magnetic field of magnitude B = 1.2 T. The coil rotates by 90° clockwise until it occupies a vertical position. This process takes 0.02 s. Calculate:

- The induced electromotive force on the coil
- The magnitude and direction of the induced current in the 12 Ω resistor.

- First, we have to calculate the magnetic flux in both positions. Thus, in the initial position (as shown in the figure), we have zero flux as the area vector and the magnetic field lines are perpendicular to each other. Hence, we have ΦWhen the coil is rotated by 90° clockwise, we have θ
_{1}= B ∙ A ∙ cos θ_{1}

= (1.2 T) ∙ (0.4 m^{2}) ∙ (cos 0^{0})

= (1.2 T) ∙ (0.4 m^{2}) ∙ 0

= 0_{2}= 90°. In this case, the flux is maximal. We haveΦSince there is a single turn in the coil (N = 1), we obtain for the induced emf produced in the coil during the given time:_{2}= B ∙ A ∙ cos θ_{2}

= (1.2 T) ∙ (0.4 m^{2}) ∙ (cos 90^{0})

= (1.2 T) ∙ (0.4 m^{2}) ∙ 1

= 0.48 Wbε_{i}= -*N ∙ ∆Φ**/**Δt*

= -1 ∙*0.48 Wb-0Wb**/**0.02 s*

= 24 V - The magnitude of the induced current in the resistor is calculated using the Ohm.s Law. We have i =The direction of the induced current in the resistor is found by using the following reasoning:
*ε*_{i}*/**R*

=*24 V**/**12 Ω*

= 2A

When the coil rotates by 90° clockwise, the magnetic flux in the coil increases. As a result, more field lines enter the coil from left to right (as this is the direction of the external magnetic field B). As a result, an induced magnetic field is produced in the coil due to the change in the flux. This means the direction of the induced magnetic field B_{i}is as shown below:

Using the right hand rule (when grasping the lateral sides of the coil, the four curled fingers show the induced magnetic field while the outstretched thumb shows the direction if the induced current) we find that the induced current flows through the resistor from right to left.

As we discussed in the previous paragraphs, the key word used to describe the Lentz law is "opposition". Let's recall the situation in which a north magnetic pole moves towards or away from a circular conducting loop.

**Opposition to pole movement**. When we move the north pole of a bar magnet towards a conducting loop, the magnetic flux through the loop increases and as a result, a current is induced in the loop as discussed earlier. From the tutorial 16.5 "Magnetic Dipole Moment", we know that the loop acts as a magnetic dipole that has its own north and south pole, the moment μ*⃗*of which is directed from south to north, as shown in the figure below.The increasing flux when the magnet approaches the loop is opposed by the north pole of the magnetic dipole directed upwards. From the curled right hand rule we can find the direction of the induced current (here anticlockwise) as shown in the figure above.

When the magnet moves away from the coil, the induced current changes direction as the magnetic dipole has its south pole directed upwards.**Opposition to flux change**. When the magnet is at rest, there is no flux change. Therefore, no induced current is produced in the loop. This means no induced magnetic field exists inside and around the coil. When the magnet is moved towards the coil (the N-pole of magnet approaching the coil), the flux increases. This brings the induction of an opposite magnetic field B_{i}(the N-pole upwards) as shown in the figure above. Again, we can determine the direction of the induced current I using the curled right hand rule.

The two above approaches are confirmations of the truthfulness of the Lentz Law discussed earlier.

The Faraday's Law expresses the induced emf as a rate of flux change. The mathematical expression of Faraday's Law is

ε_{i} = -N ∙ *∆Φ*_{M}*/**Δt*

The minus sign in Faraday's law of induction is very important. The negative sign means that **the induced emf creates a current (induced current) and magnetic field (induced magnetic field) that oppose the change in flux. This statement is known as Lenz's Law**.

When we move a magnet towards to or away from a coil, we must consider two magnetic fields: one is the magnetic field B possessed by the magnet and the other is a new magnetic field produced in the coil due to the presence of the induced current. This new magnetic field is known as the induced magnetic field B_{i} and it can be in the same or opposite direction of the original magnetic field produced by the moving magnet.

The strategy used to solve problems involving the Lentz Law consists on the following steps:

- Making a sketch that helps is a better understanding of situation through visualization.
- Determining the direction of the magnetic field B.
- Determining whether the flux is increasing or decreasing.
- Determining the direction of the induced magnetic field B
_{i}. It is either added to or subtracted from the original field. However, one thing is sure: it always opposes the motion. - Using the Right Hand Rule to determine the direction of the induced current that is responsible for the induced magnetic field B
_{i}. - The direction (or polarity) of the induced emf will now drive a current in this direction and can be thought as current emerging from the positive terminal of the emf and returning to its negative terminal.

The total magnetic field produced therefore is

B_{tot} = B + B_{i}

where both fields are in the same direction and

B_{tot} = B - B_{i}

when they are in opposite direction. The magnetic flux in the second case decreases with time as less magnetic field produced by the mar magnet enter the coil. As a result, an induced emf (and therefore an induced current) will appear in the coil based on the Faraday's Law. This induced current is in the opposite direction to before.

The increasing flux when the magnet approaches the loop is opposed by the north pole of the magnetic dipole directed upwards. From the curled right hand rule we can find the direction of the induced current.

When the magnet moves away from the coil, the induced current changes direction as the magnetic dipole has its south pole directed upwards.

When the magnet is at rest, there is no flux change. Therefore, no induced current is produced in the loop. This means no induced magnetic field exists inside and around the coil. When the magnet is moved towards the coil (the N-pole of magnet approaching the coil), the flux increases. This brings the induction of an opposite magnetic field B_{i}.

**1)** A closed conducting loop by dimensions 5 cm × 2 cm is pulled out of a 2T uniform magnetic field at constant velocity v. It takes 10 s to the loop to move out of the magnetic field if initially it was entirely within the magnetic field. What is the value of the current induced in the loop after 7s if the resistance of loop is 1 Ω?

- 2 A anticlockwise
- 0.0086 A clockwise
- 0.00086 A anticlockwise
- 0.0002 A clockwise

**Correct Answer: D**

**2)** The figure shows three identical circular conducting loops placed inside uniform magnetic fields that are either increasing (Inc) or decreasing (Dec) in magnitude at identical rates. In each figure the dashed line represents a diameter. Which is true for the magnitude of the current induced in the loops?

- iA = iB while iC = 0
- iA > iB while iC = 0
- iA = iB = 0 while iC > 0
- iA = iB = iC

**Correct Answer: A**

**3)** The North pole of a bar magnet moves initially away and then towards the coil shown in the figure.

What is the direction of the induced current (if any) flows through the resistor in both cases?

- 1 - due left; 2 - no current is flowing
- 1 - due left; 2 - due right
- 1 - due right; 2 - due left
- No current is flowing through the resistor in either case as there is no battery connected in the circuit

**Correct Answer: C**

We hope you found this Physics tutorial "Lentz Law" useful. If you thought the guide useful, it would be great if you could spare the time to rate this tutorial and/or share on social media, this helps us identify popular tutorials and calculators and expand our free learning resources to support our users around the world have free access to expand their knowledge of physics and other disciplines. In our next tutorial, we expand your insight and knowledge of Magnetism with ourPhysics tutorial on Self-Induction.

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